Base | Representation |
---|---|
bin | 111001110101000001101… |
… | …100110000010011000001 |
3 | 112001220110012101011200021 |
4 | 321311001230300103001 |
5 | 1010102120413000001 |
6 | 12241334523453441 |
7 | 560052053106646 |
oct | 71650154602301 |
9 | 15056405334607 |
10 | 3973947000001 |
11 | 12a2383532110 |
12 | 542216987281 |
13 | 22a9843892c4 |
14 | da4a91addcd |
15 | 6d588b37ba1 |
hex | 39d41b304c1 |
3973947000001 has 64 divisors (see below), whose sum is σ = 4566256436736. Its totient is φ = 3426395904000.
The previous prime is 3973946999987. The next prime is 3973947000007. The reversal of 3973947000001 is 1000007493793.
It is a cyclic number.
It is not a de Polignac number, because 3973947000001 - 27 = 3973946999873 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3973947000007) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2661718611 + ... + 2661720103.
It is an arithmetic number, because the mean of its divisors is an integer number (71347756824).
Almost surely, 23973947000001 is an apocalyptic number.
It is an amenable number.
3973947000001 is a deficient number, since it is larger than the sum of its proper divisors (592309436735).
3973947000001 is a wasteful number, since it uses less digits than its factorization.
3973947000001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2602.
The product of its (nonzero) digits is 142884, while the sum is 43.
The spelling of 3973947000001 in words is "three trillion, nine hundred seventy-three billion, nine hundred forty-seven million, one", and thus it is an aban number.
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