Base | Representation |
---|---|
bin | 111001110101000001101… |
… | …100110000010011000111 |
3 | 112001220110012101011200111 |
4 | 321311001230300103013 |
5 | 1010102120413000012 |
6 | 12241334523453451 |
7 | 560052053106655 |
oct | 71650154602307 |
9 | 15056405334614 |
10 | 3973947000007 |
11 | 12a2383532116 |
12 | 542216987287 |
13 | 22a9843892ca |
14 | da4a91addd5 |
15 | 6d588b37ba7 |
hex | 39d41b304c7 |
3973947000007 has 2 divisors, whose sum is σ = 3973947000008. Its totient is φ = 3973947000006.
The previous prime is 3973946999987. The next prime is 3973947000011. The reversal of 3973947000007 is 7000007493793.
It is a strong prime.
It is an emirp because it is prime and its reverse (7000007493793) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3973947000007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3973947000047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1986973500003 + 1986973500004.
It is an arithmetic number, because the mean of its divisors is an integer number (1986973500004).
Almost surely, 23973947000007 is an apocalyptic number.
3973947000007 is a deficient number, since it is larger than the sum of its proper divisors (1).
3973947000007 is an equidigital number, since it uses as much as digits as its factorization.
3973947000007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1000188, while the sum is 49.
The spelling of 3973947000007 in words is "three trillion, nine hundred seventy-three billion, nine hundred forty-seven million, seven", and thus it is an aban number.
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