Base | Representation |
---|---|
bin | 111001110110101100101… |
… | …001110111001100111111 |
3 | 112002002002020212100011102 |
4 | 321312230221313030333 |
5 | 1010114304244411332 |
6 | 12242232544043315 |
7 | 560144402226254 |
oct | 71665451671477 |
9 | 15062066770142 |
10 | 3975741403967 |
11 | 12a31144143a3 |
12 | 54263790353b |
13 | 22abac06a1b8 |
14 | da5d962b42b |
15 | 6d641438062 |
hex | 39daca7733f |
3975741403967 has 2 divisors, whose sum is σ = 3975741403968. Its totient is φ = 3975741403966.
The previous prime is 3975741403903. The next prime is 3975741403973. The reversal of 3975741403967 is 7693041475793.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3975741403967 - 26 = 3975741403903 is a prime.
It is a super-2 number, since 2×39757414039672 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3975741403367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1987870701983 + 1987870701984.
It is an arithmetic number, because the mean of its divisors is an integer number (1987870701984).
Almost surely, 23975741403967 is an apocalyptic number.
3975741403967 is a deficient number, since it is larger than the sum of its proper divisors (1).
3975741403967 is an equidigital number, since it uses as much as digits as its factorization.
3975741403967 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120022560, while the sum is 65.
The spelling of 3975741403967 in words is "three trillion, nine hundred seventy-five billion, seven hundred forty-one million, four hundred three thousand, nine hundred sixty-seven".
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