Base | Representation |
---|---|
bin | 10010000110001010110111… |
… | …10110001111010010110101 |
3 | 12012220022100001121101210011 |
4 | 21003011123312033102311 |
5 | 20203442424203130032 |
6 | 220345145000100221 |
7 | 11245023435636262 |
oct | 1103053366172265 |
9 | 165808301541704 |
10 | 39794412942517 |
11 | 117527967389a2 |
12 | 4568510464671 |
13 | 192879b90311c |
14 | 9b80ba39c269 |
15 | 49022602d247 |
hex | 24315bd8f4b5 |
39794412942517 has 2 divisors, whose sum is σ = 39794412942518. Its totient is φ = 39794412942516.
The previous prime is 39794412942503. The next prime is 39794412942659. The reversal of 39794412942517 is 71524921449793.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30696763497156 + 9097649445361 = 5540466^2 + 3016231^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-39794412942517 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (39794412952517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19897206471258 + 19897206471259.
It is an arithmetic number, because the mean of its divisors is an integer number (19897206471259).
Almost surely, 239794412942517 is an apocalyptic number.
It is an amenable number.
39794412942517 is a deficient number, since it is larger than the sum of its proper divisors (1).
39794412942517 is an equidigital number, since it uses as much as digits as its factorization.
39794412942517 is an evil number, because the sum of its binary digits is even.
The product of its digits is 137168640, while the sum is 67.
The spelling of 39794412942517 in words is "thirty-nine trillion, seven hundred ninety-four billion, four hundred twelve million, nine hundred forty-two thousand, five hundred seventeen".
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