Base | Representation |
---|---|
bin | 1110110101001001… |
… | …1100110000000111 |
3 | 101021110000121111012 |
4 | 3231102130300013 |
5 | 31123121132201 |
6 | 1455011232435 |
7 | 200440152362 |
oct | 35522346007 |
9 | 11243017435 |
10 | 3981036551 |
11 | 1763211758 |
12 | 9312a871b |
13 | 4b5a1203b |
14 | 29aa190d9 |
15 | 18477b5bb |
hex | ed49cc07 |
3981036551 has 2 divisors, whose sum is σ = 3981036552. Its totient is φ = 3981036550.
The previous prime is 3981036547. The next prime is 3981036569. The reversal of 3981036551 is 1556301893.
3981036551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3981036551 - 22 = 3981036547 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3981036499 and 3981036508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3981036511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1990518275 + 1990518276.
It is an arithmetic number, because the mean of its divisors is an integer number (1990518276).
Almost surely, 23981036551 is an apocalyptic number.
3981036551 is a deficient number, since it is larger than the sum of its proper divisors (1).
3981036551 is an equidigital number, since it uses as much as digits as its factorization.
3981036551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 41.
The square root of 3981036551 is about 63095.4558664885. The cubic root of 3981036551 is about 1584.8885273566. Note that the first 3 decimals are identical.
The spelling of 3981036551 in words is "three billion, nine hundred eighty-one million, thirty-six thousand, five hundred fifty-one".
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