Base | Representation |
---|---|
bin | 111010000010011100011… |
… | …110100101011011000011 |
3 | 112010021122022102001001012 |
4 | 322002130132211123003 |
5 | 1010321122324221422 |
6 | 12252120331231135 |
7 | 561102103261043 |
oct | 72023436453303 |
9 | 15107568361035 |
10 | 3988354913987 |
11 | 12a84a7411144 |
12 | 544b77ba84ab |
13 | 22c13c34a9b2 |
14 | db07490b723 |
15 | 6db2d9944e2 |
hex | 3a09c7a56c3 |
3988354913987 has 2 divisors, whose sum is σ = 3988354913988. Its totient is φ = 3988354913986.
The previous prime is 3988354913971. The next prime is 3988354913989. The reversal of 3988354913987 is 7893194538893.
3988354913987 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3988354913987 - 24 = 3988354913971 is a prime.
Together with 3988354913989, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3988354913989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1994177456993 + 1994177456994.
It is an arithmetic number, because the mean of its divisors is an integer number (1994177456994).
Almost surely, 23988354913987 is an apocalyptic number.
3988354913987 is a deficient number, since it is larger than the sum of its proper divisors (1).
3988354913987 is an equidigital number, since it uses as much as digits as its factorization.
3988354913987 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1410877440, while the sum is 77.
The spelling of 3988354913987 in words is "three trillion, nine hundred eighty-eight billion, three hundred fifty-four million, nine hundred thirteen thousand, nine hundred eighty-seven".
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