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399049191253 is a prime number
BaseRepresentation
bin1011100111010010010…
…11110110111101010101
31102011000102110021121001
411303221023312331111
523014223043110003
6503153133023301
740554545105566
oct5635113667525
91364012407531
10399049191253
11144265957749
1265408924b31
132b82666540b
1415457bbc16d
15a5a81d261d
hex5ce92f6f55

399049191253 has 2 divisors, whose sum is σ = 399049191254. Its totient is φ = 399049191252.

The previous prime is 399049191239. The next prime is 399049191257. The reversal of 399049191253 is 352191940993.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 208060962769 + 190988228484 = 456137^2 + 437022^2 .

It is a cyclic number.

It is not a de Polignac number, because 399049191253 - 213 = 399049183061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 399049191194 and 399049191203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (399049191257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 199524595626 + 199524595627.

It is an arithmetic number, because the mean of its divisors is an integer number (199524595627).

Almost surely, 2399049191253 is an apocalyptic number.

It is an amenable number.

399049191253 is a deficient number, since it is larger than the sum of its proper divisors (1).

399049191253 is an equidigital number, since it uses as much as digits as its factorization.

399049191253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2361960, while the sum is 55.

The spelling of 399049191253 in words is "three hundred ninety-nine billion, forty-nine million, one hundred ninety-one thousand, two hundred fifty-three".