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39920537951267 is a prime number
BaseRepresentation
bin10010001001110101110010…
…11110111101110000100011
312020100100212221001200201112
421010322321132331300203
520213024230203420032
6220523124132453535
711260110100552121
oct1104727136756043
9166310787050645
1039920537951267
11117a1228a46816
124588a4b47a2ab
13193764ba44c0c
149c0242d74911
15493658ab11b2
hex244eb97bdc23

39920537951267 has 2 divisors, whose sum is σ = 39920537951268. Its totient is φ = 39920537951266.

The previous prime is 39920537951201. The next prime is 39920537951269. The reversal of 39920537951267 is 76215973502993.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 39920537951267 - 222 = 39920533756963 is a prime.

Together with 39920537951269, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 39920537951197 and 39920537951206.

It is not a weakly prime, because it can be changed into another prime (39920537951269) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19960268975633 + 19960268975634.

It is an arithmetic number, because the mean of its divisors is an integer number (19960268975634).

Almost surely, 239920537951267 is an apocalyptic number.

39920537951267 is a deficient number, since it is larger than the sum of its proper divisors (1).

39920537951267 is an equidigital number, since it uses as much as digits as its factorization.

39920537951267 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192893400, while the sum is 68.

The spelling of 39920537951267 in words is "thirty-nine trillion, nine hundred twenty billion, five hundred thirty-seven million, nine hundred fifty-one thousand, two hundred sixty-seven".