Base | Representation |
---|---|
bin | 111010000110000101111… |
… | …111011001010001011111 |
3 | 112010122202100020102120121 |
4 | 322012011333121101133 |
5 | 1010402133241400203 |
6 | 12254005201055411 |
7 | 561301144150402 |
oct | 72060577312137 |
9 | 15118670212517 |
10 | 3992272606303 |
11 | 12aa127898393 |
12 | 545890027567 |
13 | 22c614bb1827 |
14 | db326d57d39 |
15 | 6dcac8ac0bd |
hex | 3a185fd945f |
3992272606303 has 2 divisors, whose sum is σ = 3992272606304. Its totient is φ = 3992272606302.
The previous prime is 3992272606277. The next prime is 3992272606373. The reversal of 3992272606303 is 3036062722993.
3992272606303 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (3036062722993) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3992272606303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3992272606373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1996136303151 + 1996136303152.
It is an arithmetic number, because the mean of its divisors is an integer number (1996136303152).
Almost surely, 23992272606303 is an apocalyptic number.
3992272606303 is a deficient number, since it is larger than the sum of its proper divisors (1).
3992272606303 is an equidigital number, since it uses as much as digits as its factorization.
3992272606303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4408992, while the sum is 52.
The spelling of 3992272606303 in words is "three trillion, nine hundred ninety-two billion, two hundred seventy-two million, six hundred six thousand, three hundred three".
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