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3996067433 is a prime number
BaseRepresentation
bin1110111000101111…
…0010011001101001
3101022111022020222112
43232023302121221
531140443124213
61500305332105
7201012004241
oct35613623151
911274266875
103996067433
111770748676
12936337035
134b8b75757
1429ca0cb21
15185c49ea8
hexee2f2669

3996067433 has 2 divisors, whose sum is σ = 3996067434. Its totient is φ = 3996067432.

The previous prime is 3996067409. The next prime is 3996067487. The reversal of 3996067433 is 3347606993.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3737243689 + 258823744 = 61133^2 + 16088^2 .

It is an emirp because it is prime and its reverse (3347606993) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3996067433 - 210 = 3996066409 is a prime.

It is not a weakly prime, because it can be changed into another prime (3996367433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1998033716 + 1998033717.

It is an arithmetic number, because the mean of its divisors is an integer number (1998033717).

Almost surely, 23996067433 is an apocalyptic number.

It is an amenable number.

3996067433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3996067433 is an equidigital number, since it uses as much as digits as its factorization.

3996067433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2204496, while the sum is 50.

The square root of 3996067433 is about 63214.4558862923. The cubic root of 3996067433 is about 1586.8806679778.

The spelling of 3996067433 in words is "three billion, nine hundred ninety-six million, sixty-seven thousand, four hundred thirty-three".