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399791124493 is a prime number
BaseRepresentation
bin1011101000101010110…
…10000111000000001101
31102012221010112101122221
411310111122013000031
523022233011440433
6503354515135341
740612124326345
oct5642532070015
91365833471587
10399791124493
11144606738112
12655952a4551
132b914297277
14154c854dd25
15a5ed3d972d
hex5d1568700d

399791124493 has 2 divisors, whose sum is σ = 399791124494. Its totient is φ = 399791124492.

The previous prime is 399791124479. The next prime is 399791124547. The reversal of 399791124493 is 394421197993.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 250333110889 + 149458013604 = 500333^2 + 386598^2 .

It is an emirp because it is prime and its reverse (394421197993) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 399791124493 - 25 = 399791124461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (399791124433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 199895562246 + 199895562247.

It is an arithmetic number, because the mean of its divisors is an integer number (199895562247).

Almost surely, 2399791124493 is an apocalyptic number.

It is an amenable number.

399791124493 is a deficient number, since it is larger than the sum of its proper divisors (1).

399791124493 is an equidigital number, since it uses as much as digits as its factorization.

399791124493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13226976, while the sum is 61.

The spelling of 399791124493 in words is "three hundred ninety-nine billion, seven hundred ninety-one million, one hundred twenty-four thousand, four hundred ninety-three".