Base | Representation |
---|---|
bin | 100101001111000100… |
… | …001001101110101001 |
3 | 10211012100200002201122 |
4 | 211033010021232221 |
5 | 1123340141203103 |
6 | 30211143425025 |
7 | 2613525354155 |
oct | 451704115651 |
9 | 124170602648 |
10 | 39981194153 |
11 | 15a57383a1a |
12 | 78b9755175 |
13 | 3a021c9844 |
14 | 1d13cb4065 |
15 | 109001eb38 |
hex | 94f109ba9 |
39981194153 has 2 divisors, whose sum is σ = 39981194154. Its totient is φ = 39981194152.
The previous prime is 39981194129. The next prime is 39981194173. The reversal of 39981194153 is 35149118993.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34376126464 + 5605067689 = 185408^2 + 74867^2 .
It is a cyclic number.
It is not a de Polignac number, because 39981194153 - 222 = 39976999849 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 39981194095 and 39981194104.
It is not a weakly prime, because it can be changed into another prime (39981194173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19990597076 + 19990597077.
It is an arithmetic number, because the mean of its divisors is an integer number (19990597077).
Almost surely, 239981194153 is an apocalyptic number.
It is an amenable number.
39981194153 is a deficient number, since it is larger than the sum of its proper divisors (1).
39981194153 is an equidigital number, since it uses as much as digits as its factorization.
39981194153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1049760, while the sum is 53.
The spelling of 39981194153 in words is "thirty-nine billion, nine hundred eighty-one million, one hundred ninety-four thousand, one hundred fifty-three".
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