Base | Representation |
---|---|
bin | 111010001101011001111… |
… | …110000101100010111001 |
3 | 112011102000112000120120002 |
4 | 322031121332011202321 |
5 | 1011014223221003231 |
6 | 12301344231442345 |
7 | 561666541665332 |
oct | 72153176054271 |
9 | 15142015016502 |
10 | 4000124000441 |
11 | 1302496795a78 |
12 | 5473015263b5 |
13 | 2302966c348a |
14 | db86d9bb289 |
15 | 6e0bbd010cb |
hex | 3a359f858b9 |
4000124000441 has 2 divisors, whose sum is σ = 4000124000442. Its totient is φ = 4000124000440.
The previous prime is 4000124000437. The next prime is 4000124000459. The reversal of 4000124000441 is 1440004210004.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3153394608400 + 846729392041 = 1775780^2 + 920179^2 .
It is a cyclic number.
It is not a de Polignac number, because 4000124000441 - 22 = 4000124000437 is a prime.
It is not a weakly prime, because it can be changed into another prime (4000124000401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2000062000220 + 2000062000221.
It is an arithmetic number, because the mean of its divisors is an integer number (2000062000221).
Almost surely, 24000124000441 is an apocalyptic number.
It is an amenable number.
4000124000441 is a deficient number, since it is larger than the sum of its proper divisors (1).
4000124000441 is an equidigital number, since it uses as much as digits as its factorization.
4000124000441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 512, while the sum is 20.
Adding to 4000124000441 its reverse (1440004210004), we get a palindrome (5440128210445).
The spelling of 4000124000441 in words is "four trillion, one hundred twenty-four million, four hundred forty-one", and thus it is an aban number.
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