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4000124000441 is a prime number
BaseRepresentation
bin111010001101011001111…
…110000101100010111001
3112011102000112000120120002
4322031121332011202321
51011014223221003231
612301344231442345
7561666541665332
oct72153176054271
915142015016502
104000124000441
111302496795a78
125473015263b5
132302966c348a
14db86d9bb289
156e0bbd010cb
hex3a359f858b9

4000124000441 has 2 divisors, whose sum is σ = 4000124000442. Its totient is φ = 4000124000440.

The previous prime is 4000124000437. The next prime is 4000124000459. The reversal of 4000124000441 is 1440004210004.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3153394608400 + 846729392041 = 1775780^2 + 920179^2 .

It is a cyclic number.

It is not a de Polignac number, because 4000124000441 - 22 = 4000124000437 is a prime.

It is not a weakly prime, because it can be changed into another prime (4000124000401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2000062000220 + 2000062000221.

It is an arithmetic number, because the mean of its divisors is an integer number (2000062000221).

Almost surely, 24000124000441 is an apocalyptic number.

It is an amenable number.

4000124000441 is a deficient number, since it is larger than the sum of its proper divisors (1).

4000124000441 is an equidigital number, since it uses as much as digits as its factorization.

4000124000441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 512, while the sum is 20.

Adding to 4000124000441 its reverse (1440004210004), we get a palindrome (5440128210445).

The spelling of 4000124000441 in words is "four trillion, one hundred twenty-four million, four hundred forty-one", and thus it is an aban number.