400013113230333 has 24 divisors (see below), whose sum is σ = 589105385751168. Its totient is φ = 261462978777312.

The previous prime is 400013113230293. The next prime is 400013113230337. The reversal of 400013113230333 is 333032311310004.

400013113230333 is a `hidden beast` number, since 4 + 0 + 0 + 0 + 1 + 3 + 1 + 1 + 323 + 0 + 333 = 666.

It is not a de Polignac number, because 400013113230333 - 2²⁰ = 400013112181757 is a prime.

It is a super-2 number, since 2×400013113230333² (a number of 30 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 400013113230297 and 400013113230306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (400013113230337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 289082385 + ... + 290462822.

It is an arithmetic number, because the mean of its divisors is an integer number (24546057739632).

Almost surely, 2^{400013113230333} is an apocalyptic number.

It is an amenable number.

400013113230333 is a deficient number, since it is larger than the sum of its proper divisors (189092272520835).

400013113230333 is a wasteful number, since it uses less digits than its factorization.

400013113230333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 579546713 (or 579546710 counting only the distinct ones).

The product of its (nonzero) digits is 5832, while the sum is 27.

Adding to 400013113230333 its reverse (333032311310004), we get a palindrome (733045424540337).

The spelling of 400013113230333 in words is "four hundred trillion, thirteen billion, one hundred thirteen million, two hundred thirty thousand, three hundred thirty-three".