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4000230147413 is a prime number
BaseRepresentation
bin111010001101100000010…
…011000000010101010101
3112011102021220202101211102
4322031200103000111111
51011014432404204123
612301402542515445
7562002301141613
oct72154023002525
915142256671742
104000230147413
1113025406a5845
12547330b95b85
132302b26a9b36
14db87db2c6b3
156e0c62bc028
hex3a3604c0555

4000230147413 has 2 divisors, whose sum is σ = 4000230147414. Its totient is φ = 4000230147412.

The previous prime is 4000230147343. The next prime is 4000230147481. The reversal of 4000230147413 is 3147410320004.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3860431180804 + 139798966609 = 1964798^2 + 373897^2 .

It is a cyclic number.

It is not a de Polignac number, because 4000230147413 - 226 = 4000163038549 is a prime.

It is a super-3 number, since 3×40002301474133 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4000230147013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2000115073706 + 2000115073707.

It is an arithmetic number, because the mean of its divisors is an integer number (2000115073707).

Almost surely, 24000230147413 is an apocalyptic number.

It is an amenable number.

4000230147413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4000230147413 is an equidigital number, since it uses as much as digits as its factorization.

4000230147413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 29.

Adding to 4000230147413 its reverse (3147410320004), we get a palindrome (7147640467417).

The spelling of 4000230147413 in words is "four trillion, two hundred thirty million, one hundred forty-seven thousand, four hundred thirteen".