Base | Representation |
---|---|
bin | 111010001101100000010… |
… | …011010100110101010111 |
3 | 112011102021220220200000102 |
4 | 322031200103110311113 |
5 | 1011014432414401013 |
6 | 12301402544404315 |
7 | 562002301641461 |
oct | 72154023246527 |
9 | 15142256820012 |
10 | 4000230231383 |
11 | 1302540752941 |
12 | 54733101669b |
13 | 2302b2709119 |
14 | db87db51131 |
15 | 6e0c62d6d58 |
hex | 3a3604d4d57 |
4000230231383 has 2 divisors, whose sum is σ = 4000230231384. Its totient is φ = 4000230231382.
The previous prime is 4000230231367. The next prime is 4000230231463. The reversal of 4000230231383 is 3831320320004.
4000230231383 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4000230231383 - 24 = 4000230231367 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4000230233383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2000115115691 + 2000115115692.
It is an arithmetic number, because the mean of its divisors is an integer number (2000115115692).
Almost surely, 24000230231383 is an apocalyptic number.
4000230231383 is a deficient number, since it is larger than the sum of its proper divisors (1).
4000230231383 is an equidigital number, since it uses as much as digits as its factorization.
4000230231383 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 4000230231383 its reverse (3831320320004), we get a palindrome (7831550551387).
The spelling of 4000230231383 in words is "four trillion, two hundred thirty million, two hundred thirty-one thousand, three hundred eighty-three".
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