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4000340043341 is a prime number
BaseRepresentation
bin111010001101100110110…
…110001110011001001101
3112011102120120112200200222
4322031212312032121031
51011020144022341331
612301421510201125
7562005104221115
oct72154666163115
915142516480628
104000340043341
111302597736224
125473619531a5
132302cc3a6a05
14db890578045
156e0d0c78b7b
hex3a366d8e64d

4000340043341 has 2 divisors, whose sum is σ = 4000340043342. Its totient is φ = 4000340043340.

The previous prime is 4000340043289. The next prime is 4000340043361. The reversal of 4000340043341 is 1433400430004.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3284250062500 + 716089980841 = 1812250^2 + 846221^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4000340043341 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4000340043341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4000340043361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2000170021670 + 2000170021671.

It is an arithmetic number, because the mean of its divisors is an integer number (2000170021671).

Almost surely, 24000340043341 is an apocalyptic number.

It is an amenable number.

4000340043341 is a deficient number, since it is larger than the sum of its proper divisors (1).

4000340043341 is an equidigital number, since it uses as much as digits as its factorization.

4000340043341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 26.

Adding to 4000340043341 its reverse (1433400430004), we get a palindrome (5433740473345).

The spelling of 4000340043341 in words is "four trillion, three hundred forty million, forty-three thousand, three hundred forty-one".