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400111203313301 is a prime number
BaseRepresentation
bin101101011111001100010011…
…0001001001110011010010101
31221110200020221200220202001012
41122332120212021032122111
5404420410221022011201
63534544314351542005
7150164036416330664
oct13276304611163225
91843606850822035
10400111203313301
11106540232435907
1238a6029452a905
131423442b12c25c
1470b36b2580ddb
15313cc25bb85bb
hex16be62624e695

400111203313301 has 2 divisors, whose sum is σ = 400111203313302. Its totient is φ = 400111203313300.

The previous prime is 400111203313249. The next prime is 400111203313313. The reversal of 400111203313301 is 103313302111004.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 283432881766225 + 116678321547076 = 16835465^2 + 10801774^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-400111203313301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (400111203313501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200055601656650 + 200055601656651.

It is an arithmetic number, because the mean of its divisors is an integer number (200055601656651).

Almost surely, 2400111203313301 is an apocalyptic number.

It is an amenable number.

400111203313301 is a deficient number, since it is larger than the sum of its proper divisors (1).

400111203313301 is an equidigital number, since it uses as much as digits as its factorization.

400111203313301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 400111203313301 its reverse (103313302111004), we get a palindrome (503424505424305).

The spelling of 400111203313301 in words is "four hundred trillion, one hundred eleven billion, two hundred three million, three hundred thirteen thousand, three hundred one".