Base | Representation |
---|---|
bin | 1011101001010010001… |
… | …00111110110111110001 |
3 | 1102020210010111102202221 |
4 | 11310221010332313301 |
5 | 23023422002133411 |
6 | 503451344241041 |
7 | 40623242331052 |
oct | 5645104766761 |
9 | 1366703442687 |
10 | 400121130481 |
11 | 144765a46536 |
12 | 65667910181 |
13 | 2b96776c997 |
14 | 1551a2d4729 |
15 | a61c374071 |
hex | 5d2913edf1 |
400121130481 has 2 divisors, whose sum is σ = 400121130482. Its totient is φ = 400121130480.
The previous prime is 400121130463. The next prime is 400121130509. The reversal of 400121130481 is 184031121004.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 270650698081 + 129470432400 = 520241^2 + 359820^2 .
It is a cyclic number.
It is not a de Polignac number, because 400121130481 - 215 = 400121097713 is a prime.
It is a super-2 number, since 2×4001211304812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (400121130181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200060565240 + 200060565241.
It is an arithmetic number, because the mean of its divisors is an integer number (200060565241).
Almost surely, 2400121130481 is an apocalyptic number.
It is an amenable number.
400121130481 is a deficient number, since it is larger than the sum of its proper divisors (1).
400121130481 is an equidigital number, since it uses as much as digits as its factorization.
400121130481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 400121130481 its reverse (184031121004), we get a palindrome (584152251485).
The spelling of 400121130481 in words is "four hundred billion, one hundred twenty-one million, one hundred thirty thousand, four hundred eighty-one".
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