4001241103331 has 2 divisors, whose sum is σ = 4001241103332. Its totient is φ = 4001241103330.

The previous prime is 4001241103241. The next prime is 4001241103333. The reversal of 4001241103331 is 1333011421004.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4001241103331 is a prime.

It is a super-2 number, since 2×4001241103331² (a number of 26 digits) contains 22 as substring.

Together with 4001241103333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4001241103297 and 4001241103306.

It is not a weakly prime, because it can be changed into another prime (4001241103333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2000620551665 + 2000620551666.

It is an arithmetic number, because the mean of its divisors is an integer number (2000620551666).

Almost surely, 2^{4001241103331} is an apocalyptic number.

4001241103331 is a deficient number, since it is larger than the sum of its proper divisors (1).

4001241103331 is an equidigital number, since it uses as much as digits as its factorization.

4001241103331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 4001241103331 its reverse (1333011421004), we get a palindrome (5334252524335).

The spelling of 4001241103331 in words is "four trillion, one billion, two hundred forty-one million, one hundred three thousand, three hundred thirty-one".