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40013401541 is a prime number
BaseRepresentation
bin100101010000111111…
…000000110111000101
310211021121021101221212
4211100333000313011
51123421412322131
630214254021205
72614366205231
oct452077006705
9124247241855
1040013401541
1115a735818a3
1279084a7805
133a08a95479
141d182995c1
151092c82a2b
hex950fc0dc5

40013401541 has 2 divisors, whose sum is σ = 40013401542. Its totient is φ = 40013401540.

The previous prime is 40013401529. The next prime is 40013401643. The reversal of 40013401541 is 14510431004.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 34356105316 + 5657296225 = 185354^2 + 75215^2 .

It is a cyclic number.

It is not a de Polignac number, because 40013401541 - 210 = 40013400517 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40013401741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20006700770 + 20006700771.

It is an arithmetic number, because the mean of its divisors is an integer number (20006700771).

Almost surely, 240013401541 is an apocalyptic number.

It is an amenable number.

40013401541 is a deficient number, since it is larger than the sum of its proper divisors (1).

40013401541 is an equidigital number, since it uses as much as digits as its factorization.

40013401541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 40013401541 its reverse (14510431004), we get a palindrome (54523832545).

The spelling of 40013401541 in words is "forty billion, thirteen million, four hundred one thousand, five hundred forty-one".