Base | Representation |
---|---|
bin | 111010001111010001101… |
… | …001000001011010100111 |
3 | 112011121012102221112112022 |
4 | 322033101221001122213 |
5 | 1011032331211310143 |
6 | 12302315352413355 |
7 | 562100361352331 |
oct | 72172151013247 |
9 | 15147172845468 |
10 | 4002131744423 |
11 | 130332704181a |
12 | 5477819a725b |
13 | 23052664c577 |
14 | db9c04d0451 |
15 | 6e1881e3268 |
hex | 3a3d1a416a7 |
4002131744423 has 2 divisors, whose sum is σ = 4002131744424. Its totient is φ = 4002131744422.
The previous prime is 4002131744371. The next prime is 4002131744467. The reversal of 4002131744423 is 3244471312004.
4002131744423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4002131744423 - 210 = 4002131743399 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4002131740423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2001065872211 + 2001065872212.
It is an arithmetic number, because the mean of its divisors is an integer number (2001065872212).
Almost surely, 24002131744423 is an apocalyptic number.
4002131744423 is a deficient number, since it is larger than the sum of its proper divisors (1).
4002131744423 is an equidigital number, since it uses as much as digits as its factorization.
4002131744423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 35.
The spelling of 4002131744423 in words is "four trillion, two billion, one hundred thirty-one million, seven hundred forty-four thousand, four hundred twenty-three".
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