Base | Representation |
---|---|
bin | 10010001101010110100100… |
… | …01010111011100010110101 |
3 | 12020202220100212002121001221 |
4 | 21012223102022323202311 |
5 | 20222013400032322010 |
6 | 221054402315350341 |
7 | 11301611353426501 |
oct | 1106532212734265 |
9 | 166686325077057 |
10 | 40041211214005 |
11 | 11838422949121 |
12 | 45a83087523b1 |
13 | 1945b405697b1 |
14 | 9c600d895301 |
15 | 49686cc06dda |
hex | 246ad22bb8b5 |
40041211214005 has 4 divisors (see below), whose sum is σ = 48049453456812. Its totient is φ = 32032968971200.
The previous prime is 40041211214003. The next prime is 40041211214029. The reversal of 40041211214005 is 50041211214004.
40041211214005 is digitally balanced in base 2 and base 6, because in such bases it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 28599884668996 + 11441326545009 = 5347886^2 + 3382503^2 .
It is not a de Polignac number, because 40041211214005 - 21 = 40041211214003 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40041211214003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4004121121396 + ... + 4004121121405.
It is an arithmetic number, because the mean of its divisors is an integer number (12012363364203).
Almost surely, 240041211214005 is an apocalyptic number.
It is an amenable number.
40041211214005 is a deficient number, since it is larger than the sum of its proper divisors (8008242242807).
40041211214005 is an equidigital number, since it uses as much as digits as its factorization.
40041211214005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8008242242806.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 40041211214005 its reverse (50041211214004), we get a palindrome (90082422428009).
Subtracting 40041211214005 from its reverse (50041211214004), we obtain a palindrome (9999999999999).
The spelling of 40041211214005 in words is "forty trillion, forty-one billion, two hundred eleven million, two hundred fourteen thousand, five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •