4010092531253 has 2 divisors, whose sum is σ = 4010092531254. Its totient is φ = 4010092531252.

The previous prime is 4010092531183. The next prime is 4010092531267. The reversal of 4010092531253 is 3521352900104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4008296297329 + 1796233924 = 2002073^2 + 42382^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4010092531253 is a prime.

It is a super-2 number, since 2×4010092531253² (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4010092531283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005046265626 + 2005046265627.

It is an arithmetic number, because the mean of its divisors is an integer number (2005046265627).

Almost surely, 2^{4010092531253} is an apocalyptic number.

It is an amenable number.

4010092531253 is a deficient number, since it is larger than the sum of its proper divisors (1).

4010092531253 is an equidigital number, since it uses as much as digits as its factorization.

4010092531253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 35.

The spelling of 4010092531253 in words is "four trillion, ten billion, ninety-two million, five hundred thirty-one thousand, two hundred fifty-three".