Base | Representation |
---|---|
bin | 101101100101101111010110… |
… | …1011111000101000000101111 |
3 | 1221120212021210120221100002022 |
4 | 1123023132231133011000233 |
5 | 410030131234231142431 |
6 | 3540513544415220355 |
7 | 150316045303142261 |
oct | 13313365537050057 |
9 | 1846767716840068 |
10 | 401011122130991 |
11 | 106857953117189 |
12 | 38b867855176bb |
13 | 1429b256b32a98 |
14 | 7105082c73b31 |
15 | 315634600b07b |
hex | 16cb7ad7c502f |
401011122130991 has 2 divisors, whose sum is σ = 401011122130992. Its totient is φ = 401011122130990.
The previous prime is 401011122130973. The next prime is 401011122131027. The reversal of 401011122130991 is 199031221110104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 401011122130991 - 214 = 401011122114607 is a prime.
It is a super-4 number, since 4×4010111221309914 (a number of 60 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (401011122130901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200505561065495 + 200505561065496.
It is an arithmetic number, because the mean of its divisors is an integer number (200505561065496).
Almost surely, 2401011122130991 is an apocalyptic number.
401011122130991 is a deficient number, since it is larger than the sum of its proper divisors (1).
401011122130991 is an equidigital number, since it uses as much as digits as its factorization.
401011122130991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 35.
The spelling of 401011122130991 in words is "four hundred one trillion, eleven billion, one hundred twenty-two million, one hundred thirty thousand, nine hundred ninety-one".
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