Base | Representation |
---|---|
bin | 10010001111001010000011… |
… | …01110011011100010010001 |
3 | 12020222211101211010210021221 |
4 | 21013211001232123202101 |
5 | 20224022334324130301 |
6 | 221143054510445041 |
7 | 11306234662310113 |
oct | 1107450156334221 |
9 | 166884354123257 |
10 | 40103212333201 |
11 | 118617499676a6 |
12 | 45b8330803781 |
13 | 194b941773584 |
14 | 9c90120153b3 |
15 | 49829ae8dda1 |
hex | 247941b9b891 |
40103212333201 has 2 divisors, whose sum is σ = 40103212333202. Its totient is φ = 40103212333200.
The previous prime is 40103212333189. The next prime is 40103212333369. The reversal of 40103212333201 is 10233321230104.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29270523730176 + 10832688603025 = 5410224^2 + 3291305^2 .
It is a cyclic number.
It is not a de Polignac number, because 40103212333201 - 215 = 40103212300433 is a prime.
It is not a weakly prime, because it can be changed into another prime (40103212633201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20051606166600 + 20051606166601.
It is an arithmetic number, because the mean of its divisors is an integer number (20051606166601).
Almost surely, 240103212333201 is an apocalyptic number.
It is an amenable number.
40103212333201 is a deficient number, since it is larger than the sum of its proper divisors (1).
40103212333201 is an equidigital number, since it uses as much as digits as its factorization.
40103212333201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 40103212333201 its reverse (10233321230104), we get a palindrome (50336533563305).
The spelling of 40103212333201 in words is "forty trillion, one hundred three billion, two hundred twelve million, three hundred thirty-three thousand, two hundred one".
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