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40108139746903 is a prime number
BaseRepresentation
bin10010001111010011001110…
…11011000001011001010111
312021000022010012221100011201
421013221213123001121113
520224112432233400103
6221145231450213331
711306501043526534
oct1107514733013127
9167008105840151
1040108139746903
11118638482a7528
1245b9286a24247
13194c248569397
149c935c5bdd8b
1549848885851d
hex247a676c1657

40108139746903 has 2 divisors, whose sum is σ = 40108139746904. Its totient is φ = 40108139746902.

The previous prime is 40108139746879. The next prime is 40108139746921. The reversal of 40108139746903 is 30964793180104.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40108139746903 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40108139746933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20054069873451 + 20054069873452.

It is an arithmetic number, because the mean of its divisors is an integer number (20054069873452).

Almost surely, 240108139746903 is an apocalyptic number.

40108139746903 is a deficient number, since it is larger than the sum of its proper divisors (1).

40108139746903 is an equidigital number, since it uses as much as digits as its factorization.

40108139746903 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3919104, while the sum is 55.

The spelling of 40108139746903 in words is "forty trillion, one hundred eight billion, one hundred thirty-nine million, seven hundred forty-six thousand, nine hundred three".