4011244011331 has 2 divisors, whose sum is σ = 4011244011332. Its totient is φ = 4011244011330.

The previous prime is 4011244011323. The next prime is 4011244011353. The reversal of 4011244011331 is 1331104421104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4011244011331 - 2³ = 4011244011323 is a prime.

It is a super-3 number, since 3×4011244011331³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 4011244011296 and 4011244011305.

It is not a weakly prime, because it can be changed into another prime (4011244011631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005622005665 + 2005622005666.

It is an arithmetic number, because the mean of its divisors is an integer number (2005622005666).

Almost surely, 2^{4011244011331} is an apocalyptic number.

4011244011331 is a deficient number, since it is larger than the sum of its proper divisors (1).

4011244011331 is an equidigital number, since it uses as much as digits as its factorization.

4011244011331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 4011244011331 its reverse (1331104421104), we get a palindrome (5342348432435).

The spelling of 4011244011331 in words is "four trillion, eleven billion, two hundred forty-four million, eleven thousand, three hundred thirty-one".