40113104321 has 2 divisors, whose sum is σ = 40113104322. Its totient is φ = 40113104320.

The previous prime is 40113104309. The next prime is 40113104333. The reversal of 40113104321 is 12340131104.

It is a balanced prime because it is at equal distance from previous prime (40113104309) and next prime (40113104333).

It can be written as a sum of positive squares in only one way, i.e., 39020471296 + 1092633025 = 197536^2 + 33055^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-40113104321 is a prime.

It is a super-3 number, since 3×40113104321³ (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 40113104293 and 40113104302.

It is not a weakly prime, because it can be changed into another prime (40113104221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20056552160 + 20056552161.

It is an arithmetic number, because the mean of its divisors is an integer number (20056552161).

Almost surely, 2^40113104321 is an apocalyptic number.

It is an amenable number.

40113104321 is a deficient number, since it is larger than the sum of its proper divisors (1).

40113104321 is an equidigital number, since it uses as much as digits as its factorization.

40113104321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 40113104321 its reverse (12340131104), we get a palindrome (52453235425).

The spelling of 40113104321 in words is "forty billion, one hundred thirteen million, one hundred four thousand, three hundred twenty-one".