Base | Representation |
---|---|
bin | 10010001111011100110000… |
… | …10000011001110010110100 |
3 | 12021000210022122100000220111 |
4 | 21013232120100121302310 |
5 | 20224203421011423012 |
6 | 221151435142512404 |
7 | 11310041554220605 |
oct | 1107563020316264 |
9 | 167023278300814 |
10 | 40113254014132 |
11 | 11865a32160162 |
12 | 45ba273735704 |
13 | 194c881c95700 |
14 | 9c96c5907dac |
15 | 498687831ba7 |
hex | 247b98419cb4 |
40113254014132 has 36 divisors (see below), whose sum is σ = 76021102614240. Its totient is φ = 18511940702112.
The previous prime is 40113254014129. The next prime is 40113254014187. The reversal of 40113254014132 is 23141045231104.
It is a happy number.
It is a super-2 number, since 2×401132540141322 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 40113254014094 and 40113254014103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3717969 + ... + 9697927.
It is an arithmetic number, because the mean of its divisors is an integer number (2111697294840).
Almost surely, 240113254014132 is an apocalyptic number.
It is an amenable number.
40113254014132 is a deficient number, since it is larger than the sum of its proper divisors (35907848600108).
40113254014132 is a wasteful number, since it uses less digits than its factorization.
40113254014132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5989912 (or 5989897 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 40113254014132 its reverse (23141045231104), we get a palindrome (63254299245236).
The spelling of 40113254014132 in words is "forty trillion, one hundred thirteen billion, two hundred fifty-four million, fourteen thousand, one hundred thirty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •