40113413412133 has 2 divisors, whose sum is σ = 40113413412134. Its totient is φ = 40113413412132.

The previous prime is 40113413412113. The next prime is 40113413412151. The reversal of 40113413412133 is 33121431431104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37746978836449 + 2366434575684 = 6143857^2 + 1538322^2 .

It is a cyclic number.

It is not a de Polignac number, because 40113413412133 - 2¹⁷ = 40113413281061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40113413412095 and 40113413412104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40113413412113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20056706706066 + 20056706706067.

It is an arithmetic number, because the mean of its divisors is an integer number (20056706706067).

Almost surely, 2^{40113413412133} is an apocalyptic number.

It is an amenable number.

40113413412133 is a deficient number, since it is larger than the sum of its proper divisors (1).

40113413412133 is an equidigital number, since it uses as much as digits as its factorization.

40113413412133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 40113413412133 its reverse (33121431431104), we get a palindrome (73234844843237).

The spelling of 40113413412133 in words is "forty trillion, one hundred thirteen billion, four hundred thirteen million, four hundred twelve thousand, one hundred thirty-three".