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40114330433 is a prime number
BaseRepresentation
bin100101010111000000…
…000001101101000001
310211112122012010100222
4211113000001231001
51124123232033213
630232301152425
72620033116452
oct452700015501
9124478163328
1040114330433
1116015548201
12793625b715
133a239729c8
141d2784d129
15109ba6c808
hex957001b41

40114330433 has 2 divisors, whose sum is σ = 40114330434. Its totient is φ = 40114330432.

The previous prime is 40114330411. The next prime is 40114330463. The reversal of 40114330433 is 33403341104.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30284004529 + 9830325904 = 174023^2 + 99148^2 .

It is a cyclic number.

It is not a de Polignac number, because 40114330433 - 214 = 40114314049 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (40114330463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20057165216 + 20057165217.

It is an arithmetic number, because the mean of its divisors is an integer number (20057165217).

Almost surely, 240114330433 is an apocalyptic number.

It is an amenable number.

40114330433 is a deficient number, since it is larger than the sum of its proper divisors (1).

40114330433 is an equidigital number, since it uses as much as digits as its factorization.

40114330433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 40114330433 its reverse (33403341104), we get a palindrome (73517671537).

The spelling of 40114330433 in words is "forty billion, one hundred fourteen million, three hundred thirty thousand, four hundred thirty-three".