Base | Representation |
---|---|
bin | 10010001111100000100010… |
… | …11101000101001001000111 |
3 | 12021000222120100110202020212 |
4 | 21013300101131011021013 |
5 | 20224222102032134201 |
6 | 221152413020550035 |
7 | 11310143134441565 |
oct | 1107602135051107 |
9 | 167028510422225 |
10 | 40115287380551 |
11 | 11866885a17479 |
12 | 45ba7406b231b |
13 | 194cb173230c6 |
14 | 9c98399aaa35 |
15 | 4987560d5abb |
hex | 247c11745247 |
40115287380551 has 2 divisors, whose sum is σ = 40115287380552. Its totient is φ = 40115287380550.
The previous prime is 40115287380533. The next prime is 40115287380673. The reversal of 40115287380551 is 15508378251104.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40115287380551 is a prime.
It is a super-2 number, since 2×401152873805512 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 40115287380551.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40115287380521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20057643690275 + 20057643690276.
It is an arithmetic number, because the mean of its divisors is an integer number (20057643690276).
Almost surely, 240115287380551 is an apocalyptic number.
40115287380551 is a deficient number, since it is larger than the sum of its proper divisors (1).
40115287380551 is an equidigital number, since it uses as much as digits as its factorization.
40115287380551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344000, while the sum is 50.
The spelling of 40115287380551 in words is "forty trillion, one hundred fifteen billion, two hundred eighty-seven million, three hundred eighty thousand, five hundred fifty-one".
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