Base | Representation |
---|---|
bin | 111010011000011111001… |
… | …010100111010000110111 |
3 | 112012112201201211100212022 |
4 | 322120133022213100313 |
5 | 1011213110204033143 |
6 | 12311033030143355 |
7 | 562600440063122 |
oct | 72303712472067 |
9 | 15175651740768 |
10 | 4012022330423 |
11 | 1307542015438 |
12 | 5496821b1b5b |
13 | 23144177b313 |
14 | dc27bcd13b9 |
15 | 6e56668c268 |
hex | 3a61f2a7437 |
4012022330423 has 2 divisors, whose sum is σ = 4012022330424. Its totient is φ = 4012022330422.
The previous prime is 4012022330419. The next prime is 4012022330507. The reversal of 4012022330423 is 3240332202104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4012022330423 - 22 = 4012022330419 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4012022330392 and 4012022330401.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4012022330123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006011165211 + 2006011165212.
It is an arithmetic number, because the mean of its divisors is an integer number (2006011165212).
Almost surely, 24012022330423 is an apocalyptic number.
4012022330423 is a deficient number, since it is larger than the sum of its proper divisors (1).
4012022330423 is an equidigital number, since it uses as much as digits as its factorization.
4012022330423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 4012022330423 its reverse (3240332202104), we get a palindrome (7252354532527).
The spelling of 4012022330423 in words is "four trillion, twelve billion, twenty-two million, three hundred thirty thousand, four hundred twenty-three".
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