Base | Representation |
---|---|
bin | 101101100111001100000000… |
… | …1100000001101110101001111 |
3 | 1221121120022101201022002221000 |
4 | 1123032120001200031311033 |
5 | 410041411241123223043 |
6 | 3541145213042111343 |
7 | 150336321205001625 |
oct | 13316300140156517 |
9 | 1847508351262830 |
10 | 401210100211023 |
11 | 106924280052824 |
12 | 38bb925694b553 |
13 | 142b3c4750b78c |
14 | 711095b33d515 |
15 | 315b5de8be2d3 |
hex | 16ce60180dd4f |
401210100211023 has 16 divisors (see below), whose sum is σ = 595838598536800. Its totient is φ = 266819430939840.
The previous prime is 401210100211021. The next prime is 401210100211051. The reversal of 401210100211023 is 320112001012104.
401210100211023 is a `hidden beast` number, since 401 + 21 + 0 + 10 + 0 + 211 + 0 + 23 = 666.
It is not a de Polignac number, because 401210100211023 - 21 = 401210100211021 is a prime.
It is a super-2 number, since 2×4012101002110232 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 401210100210987 and 401210100211005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (401210100211021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18165799888 + ... + 18165821973.
It is an arithmetic number, because the mean of its divisors is an integer number (37239912408550).
Almost surely, 2401210100211023 is an apocalyptic number.
401210100211023 is a deficient number, since it is larger than the sum of its proper divisors (194628498325777).
401210100211023 is a wasteful number, since it uses less digits than its factorization.
401210100211023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36331622279 (or 36331622273 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 401210100211023 its reverse (320112001012104), we get a palindrome (721322101223127).
The spelling of 401210100211023 in words is "four hundred one trillion, two hundred ten billion, one hundred million, two hundred eleven thousand, twenty-three".
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