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401232242605643 is a prime number
BaseRepresentation
bin101101100111010110010100…
…1010010101111111001001011
31221121122102112212010022002122
41123032230221102233321023
5410042242113101340033
63541203314142321455
7150341034003153161
oct13316545122577113
91847572485108078
10401232242605643
11106932702936609
12390015b628928b
13142b60659c8a27
147111a5bd89231
15315be88778a98
hex16ceb294afe4b

401232242605643 has 2 divisors, whose sum is σ = 401232242605644. Its totient is φ = 401232242605642.

The previous prime is 401232242605553. The next prime is 401232242605687. The reversal of 401232242605643 is 346506242232104.

It is an a-pointer prime, because the next prime (401232242605687) can be obtained adding 401232242605643 to its sum of digits (44).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 401232242605643 - 220 = 401232241557067 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 401232242605594 and 401232242605603.

It is not a weakly prime, because it can be changed into another prime (401232242601643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200616121302821 + 200616121302822.

It is an arithmetic number, because the mean of its divisors is an integer number (200616121302822).

Almost surely, 2401232242605643 is an apocalyptic number.

401232242605643 is a deficient number, since it is larger than the sum of its proper divisors (1).

401232242605643 is an equidigital number, since it uses as much as digits as its factorization.

401232242605643 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1658880, while the sum is 44.

Adding to 401232242605643 its reverse (346506242232104), we get a palindrome (747738484837747).

The spelling of 401232242605643 in words is "four hundred one trillion, two hundred thirty-two billion, two hundred forty-two million, six hundred five thousand, six hundred forty-three".