401234256664853 has 2 divisors, whose sum is σ = 401234256664854. Its totient is φ = 401234256664852.

The previous prime is 401234256664807. The next prime is 401234256664859. The reversal of 401234256664853 is 358466652432104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 385528237726129 + 15706018938724 = 19634873^2 + 3963082^2 .

It is a cyclic number.

It is not a de Polignac number, because 401234256664853 - 2⁸ = 401234256664597 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 401234256664792 and 401234256664801.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (401234256664859) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200617128332426 + 200617128332427.

It is an arithmetic number, because the mean of its divisors is an integer number (200617128332427).

Almost surely, 2^{401234256664853} is an apocalyptic number.

It is an amenable number.

401234256664853 is a deficient number, since it is larger than the sum of its proper divisors (1).

401234256664853 is an equidigital number, since it uses as much as digits as its factorization.

401234256664853 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 99532800, while the sum is 59.

The spelling of 401234256664853 in words is "four hundred one trillion, two hundred thirty-four billion, two hundred fifty-six million, six hundred sixty-four thousand, eight hundred fifty-three".