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4012685891153 is a prime number
BaseRepresentation
bin111010011001000110101…
…101111001011001010001
3112012121102222102202001122
4322121012231321121101
51011220440042004103
612311222532412025
7562623045206402
oct72310655713121
915177388382048
104012685891153
111307852636435
12549828477015
1323151909c7c4
14dc3020a19a9
156e5a4a62b38
hex3a646b79651

4012685891153 has 2 divisors, whose sum is σ = 4012685891154. Its totient is φ = 4012685891152.

The previous prime is 4012685891143. The next prime is 4012685891239. The reversal of 4012685891153 is 3511985862104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3167485146049 + 845200745104 = 1779743^2 + 919348^2 .

It is a cyclic number.

It is not a de Polignac number, because 4012685891153 - 212 = 4012685887057 is a prime.

It is a super-2 number, since 2×40126858911532 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4012685891095 and 4012685891104.

It is not a weakly prime, because it can be changed into another prime (4012685891143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006342945576 + 2006342945577.

It is an arithmetic number, because the mean of its divisors is an integer number (2006342945577).

Almost surely, 24012685891153 is an apocalyptic number.

It is an amenable number.

4012685891153 is a deficient number, since it is larger than the sum of its proper divisors (1).

4012685891153 is an equidigital number, since it uses as much as digits as its factorization.

4012685891153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2073600, while the sum is 53.

The spelling of 4012685891153 in words is "four trillion, twelve billion, six hundred eighty-five million, eight hundred ninety-one thousand, one hundred fifty-three".