40127139853 has 2 divisors, whose sum is σ = 40127139854. Its totient is φ = 40127139852.

The previous prime is 40127139839. The next prime is 40127139859. The reversal of 40127139853 is 35893172104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34535390569 + 5591749284 = 185837^2 + 74778^2 .

It is a cyclic number.

It is not a de Polignac number, because 40127139853 - 2⁵ = 40127139821 is a prime.

It is a super-2 number, since 2×40127139853² (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40127139859) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20063569926 + 20063569927.

It is an arithmetic number, because the mean of its divisors is an integer number (20063569927).

Almost surely, 2^40127139853 is an apocalyptic number.

It is an amenable number.

40127139853 is a deficient number, since it is larger than the sum of its proper divisors (1).

40127139853 is an equidigital number, since it uses as much as digits as its factorization.

40127139853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 181440, while the sum is 43.

The spelling of 40127139853 in words is "forty billion, one hundred twenty-seven million, one hundred thirty-nine thousand, eight hundred fifty-three".