4012805131 has 2 divisors, whose sum is σ = 4012805132. Its totient is φ = 4012805130.

The previous prime is 4012805117. The next prime is 4012805189. The reversal of 4012805131 is 1315082104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4012805131 - 2⁵ = 4012805099 is a prime.

It is a super-2 number, since 2×4012805131² = 32205210038759854322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4012805096 and 4012805105.

It is not a weakly prime, because it can be changed into another prime (4012805191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006402565 + 2006402566.

It is an arithmetic number, because the mean of its divisors is an integer number (2006402566).

Almost surely, 2^4012805131 is an apocalyptic number.

4012805131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4012805131 is an equidigital number, since it uses as much as digits as its factorization.

4012805131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 25.

The square root of 4012805131 is about 63346.7057628098. The cubic root of 4012805131 is about 1589.0931541532.

Adding to 4012805131 its reverse (1315082104), we get a palindrome (5327887235).

The spelling of 4012805131 in words is "four billion, twelve million, eight hundred five thousand, one hundred thirty-one".