Base | Representation |
---|---|
bin | 111010011001001111111… |
… | …011010101000111111111 |
3 | 112012121211202011222201012 |
4 | 322121033323111013333 |
5 | 1011221244121020201 |
6 | 12311250132305435 |
7 | 562626632446463 |
oct | 72311773250777 |
9 | 15177752158635 |
10 | 4012840407551 |
11 | 1307921882938 |
12 | 54987017227b |
13 | 2315420c0321 |
14 | dc3188044a3 |
15 | 6e5b33d55bb |
hex | 3a64fed51ff |
4012840407551 has 2 divisors, whose sum is σ = 4012840407552. Its totient is φ = 4012840407550.
The previous prime is 4012840407517. The next prime is 4012840407581. The reversal of 4012840407551 is 1557040482104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4012840407551 - 226 = 4012773298687 is a prime.
It is a super-2 number, since 2×40128404075512 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4012840407499 and 4012840407508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4012840407581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006420203775 + 2006420203776.
It is an arithmetic number, because the mean of its divisors is an integer number (2006420203776).
Almost surely, 24012840407551 is an apocalyptic number.
4012840407551 is a deficient number, since it is larger than the sum of its proper divisors (1).
4012840407551 is an equidigital number, since it uses as much as digits as its factorization.
4012840407551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 179200, while the sum is 41.
Adding to 4012840407551 its reverse (1557040482104), we get a palindrome (5569880889655).
The spelling of 4012840407551 in words is "four trillion, twelve billion, eight hundred forty million, four hundred seven thousand, five hundred fifty-one".
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