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4013001314322 = 23711132346762207
BaseRepresentation
bin111010011001011001100…
…001001001000000010010
3112012122020221221220022020
4322121121201021000102
51011222111314024242
612311314121152310
7562633625233440
oct72313141110022
915178227856266
104013001314322
1113079a4694540
125498b602b696
1323156953a730
14dc331d2bb90
156e5c25bb6ec
hex3a659849012

4013001314322 has 256 divisors, whose sum is σ = 11268960288768. Its totient is φ = 918339713280.

The previous prime is 4013001314321. The next prime is 4013001314341. The reversal of 4013001314322 is 2234131003104.

It is a happy number.

It is a super-2 number, since 2×40130013143222 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4013001314292 and 4013001314301.

It is not an unprimeable number, because it can be changed into a prime (4013001314321) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 64479343 + ... + 64541549.

It is an arithmetic number, because the mean of its divisors is an integer number (44019376128).

Almost surely, 24013001314322 is an apocalyptic number.

4013001314322 is a gapful number since it is divisible by the number (42) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 4013001314322, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5634480144384).

4013001314322 is an abundant number, since it is smaller than the sum of its proper divisors (7255958974446).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4013001314322 is a wasteful number, since it uses less digits than its factorization.

4013001314322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62733.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 4013001314322 its reverse (2234131003104), we get a palindrome (6247132317426).

The spelling of 4013001314322 in words is "four trillion, thirteen billion, one million, three hundred fourteen thousand, three hundred twenty-two".