Base | Representation |
---|---|
bin | 101101100111110110010111… |
… | …0101011101011100100010111 |
3 | 1221121220000011100002022220022 |
4 | 1123033230232223223210113 |
5 | 410044404023420114333 |
6 | 3541255054121255355 |
7 | 150346021116512555 |
oct | 13317545653534427 |
9 | 1847800140068808 |
10 | 401301052504343 |
11 | 106959903272992 |
12 | 390129ba63455b |
13 | 142bc6b0706614 |
14 | 71151088cabd5 |
15 | 315db64656c98 |
hex | 16cfb2eaeb917 |
401301052504343 has 2 divisors, whose sum is σ = 401301052504344. Its totient is φ = 401301052504342.
The previous prime is 401301052504327. The next prime is 401301052504379. The reversal of 401301052504343 is 343405250103104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 401301052504343 - 24 = 401301052504327 is a prime.
It is a super-2 number, since 2×4013010525043432 (a number of 30 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (401301052507343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200650526252171 + 200650526252172.
It is an arithmetic number, because the mean of its divisors is an integer number (200650526252172).
Almost surely, 2401301052504343 is an apocalyptic number.
401301052504343 is a deficient number, since it is larger than the sum of its proper divisors (1).
401301052504343 is an equidigital number, since it uses as much as digits as its factorization.
401301052504343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 35.
The spelling of 401301052504343 in words is "four hundred one trillion, three hundred one billion, fifty-two million, five hundred four thousand, three hundred forty-three".
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