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401303004221323 is a prime number
BaseRepresentation
bin101101100111110111010001…
…1000000111000111110001011
31221121220012012100120211021101
41123033232203000320332023
5410044422023040040243
63541300015521322231
7150346120356030541
oct13317564300707613
91847805170524241
10401303004221323
1110695a714a31826
1239013264196377
13142bc931b76c39
147115251bb7d91
15315dc2ab7d54d
hex16cfba3038f8b

401303004221323 has 2 divisors, whose sum is σ = 401303004221324. Its totient is φ = 401303004221322.

The previous prime is 401303004221269. The next prime is 401303004221341. The reversal of 401303004221323 is 323122400303104.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 401303004221323 - 217 = 401303004090251 is a prime.

It is a super-2 number, since 2×4013030042213232 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 401303004221291 and 401303004221300.

It is not a weakly prime, because it can be changed into another prime (401303004221363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200651502110661 + 200651502110662.

It is an arithmetic number, because the mean of its divisors is an integer number (200651502110662).

Almost surely, 2401303004221323 is an apocalyptic number.

401303004221323 is a deficient number, since it is larger than the sum of its proper divisors (1).

401303004221323 is an equidigital number, since it uses as much as digits as its factorization.

401303004221323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 401303004221323 its reverse (323122400303104), we get a palindrome (724425404524427).

The spelling of 401303004221323 in words is "four hundred one trillion, three hundred three billion, four million, two hundred twenty-one thousand, three hundred twenty-three".