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40131102031 is a prime number
BaseRepresentation
bin100101011000000000…
…000000010101001111
310211120210202012200021
4211120000000111033
51124142030231111
630234100443011
72620325511316
oct453000002517
9124523665607
1040131102031
1116023a62a29
12793b9a9467
133a27295827
141d29b7727d
15109d281d71
hex95800054f

40131102031 has 2 divisors, whose sum is σ = 40131102032. Its totient is φ = 40131102030.

The previous prime is 40131101981. The next prime is 40131102107. The reversal of 40131102031 is 13020113104.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40131102031 is a prime.

It is a super-2 number, since 2×401311020312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40131101996 and 40131102014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40131102131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065551015 + 20065551016.

It is an arithmetic number, because the mean of its divisors is an integer number (20065551016).

Almost surely, 240131102031 is an apocalyptic number.

40131102031 is a deficient number, since it is larger than the sum of its proper divisors (1).

40131102031 is an equidigital number, since it uses as much as digits as its factorization.

40131102031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 40131102031 its reverse (13020113104), we get a palindrome (53151215135).

The spelling of 40131102031 in words is "forty billion, one hundred thirty-one million, one hundred two thousand, thirty-one".