4013114033 has 2 divisors, whose sum is σ = 4013114034. Its totient is φ = 4013114032.

The previous prime is 4013114009. The next prime is 4013114057. The reversal of 4013114033 is 3304113104.

It is a balanced prime because it is at equal distance from previous prime (4013114009) and next prime (4013114057).

It can be written as a sum of positive squares in only one way, i.e., 2861394064 + 1151719969 = 53492^2 + 33937^2 .

It is a cyclic number.

It is not a de Polignac number, because 4013114033 - 2⁸ = 4013113777 is a prime.

It is a super-2 number, since 2×4013114033² = 32210168483723050178, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4013113996 and 4013114014.

It is not a weakly prime, because it can be changed into another prime (4013114003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006557016 + 2006557017.

It is an arithmetic number, because the mean of its divisors is an integer number (2006557017).

Almost surely, 2^4013114033 is an apocalyptic number.

It is an amenable number.

4013114033 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013114033 is an equidigital number, since it uses as much as digits as its factorization.

4013114033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 4013114033 is about 63349.1439010820. The cubic root of 4013114033 is about 1589.1339287437.

Adding to 4013114033 its reverse (3304113104), we get a palindrome (7317227137).

The spelling of 4013114033 in words is "four billion, thirteen million, one hundred fourteen thousand, thirty-three".