4013114313053 has 4 divisors (see below), whose sum is σ = 4036311505788. Its totient is φ = 3989917120320.

The previous prime is 4013114313049. The next prime is 4013114313071. The reversal of 4013114313053 is 3503134113104.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3711737468569 + 301376844484 = 1926587^2 + 548978^2 .

It is a cyclic number.

It is not a de Polignac number, because 4013114313053 - 2² = 4013114313049 is a prime.

It is a super-2 number, since 2×4013114313053² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4013114310053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11598596108 + ... + 11598596453.

It is an arithmetic number, because the mean of its divisors is an integer number (1009077876447).

Almost surely, 2^{4013114313053} is an apocalyptic number.

It is an amenable number.

4013114313053 is a deficient number, since it is larger than the sum of its proper divisors (23197192735).

4013114313053 is a wasteful number, since it uses less digits than its factorization.

4013114313053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23197192734.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 4013114313053 its reverse (3503134113104), we get a palindrome (7516248426157).

The spelling of 4013114313053 in words is "four trillion, thirteen billion, one hundred fourteen million, three hundred thirteen thousand, fifty-three".