4013121112000 has 448 divisors, whose sum is σ = 13344019153920. Its totient is φ = 1154621952000.

The previous prime is 4013121111997. The next prime is 4013121112003. The reversal of 4013121112000 is 2111213104.

It is an interprime number because it is at equal distance from previous prime (4013121111997) and next prime (4013121112003).

It is a tau number, because it is divible by the number of its divisors (448).

It is a super-2 number, since 2×4013121112000² (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4013121112003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7757431 + ... + 8258569.

It is an arithmetic number, because the mean of its divisors is an integer number (29785757040).

Almost surely, 2^{4013121112000} is an apocalyptic number.

4013121112000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 4013121112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6672009576960).

4013121112000 is an abundant number, since it is smaller than the sum of its proper divisors (9330898041920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4013121112000 is a wasteful number, since it uses less digits than its factorization.

4013121112000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 501197 (or 501177 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 4013121112000 its reverse (2111213104), we get a palindrome (4015232325104).

The spelling of 4013121112000 in words is "four trillion, thirteen billion, one hundred twenty-one million, one hundred twelve thousand".