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40131314327473 is a prime number
BaseRepresentation
bin10010001111111110011001…
…01111000001111110110001
312021002111221022000000021121
421013333030233001332301
520230002412431434343
6221204023222022241
711311251244313425
oct1107771457017661
9167074838000247
1040131314327473
111187265a797956
124601873b77981
13195149c852755
149ca51a354b85
15498d93150aed
hex247fccbc1fb1

40131314327473 has 2 divisors, whose sum is σ = 40131314327474. Its totient is φ = 40131314327472.

The previous prime is 40131314327413. The next prime is 40131314327513. The reversal of 40131314327473 is 37472341313104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36278600941584 + 3852713385889 = 6023172^2 + 1962833^2 .

It is a cyclic number.

It is not a de Polignac number, because 40131314327473 - 225 = 40131280773041 is a prime.

It is a super-2 number, since 2×401313143274732 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40131314327413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065657163736 + 20065657163737.

It is an arithmetic number, because the mean of its divisors is an integer number (20065657163737).

Almost surely, 240131314327473 is an apocalyptic number.

It is an amenable number.

40131314327473 is a deficient number, since it is larger than the sum of its proper divisors (1).

40131314327473 is an equidigital number, since it uses as much as digits as its factorization.

40131314327473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 508032, while the sum is 43.

The spelling of 40131314327473 in words is "forty trillion, one hundred thirty-one billion, three hundred fourteen million, three hundred twenty-seven thousand, four hundred seventy-three".