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40131314327513 is a prime number
BaseRepresentation
bin10010001111111110011001…
…01111000001111111011001
312021002111221022000000100002
421013333030233001333121
520230002412431440023
6221204023222022345
711311251244313513
oct1107771457017731
9167074838000302
1040131314327513
111187265a797992
124601873b779b5
13195149c852786
149ca51a354bb3
15498d93150b28
hex247fccbc1fd9

40131314327513 has 2 divisors, whose sum is σ = 40131314327514. Its totient is φ = 40131314327512.

The previous prime is 40131314327473. The next prime is 40131314327521. The reversal of 40131314327513 is 31572341313104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25718418396889 + 14412895930624 = 5071333^2 + 3796432^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40131314327513 is a prime.

It is a super-2 number, since 2×401313143275132 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40131314327413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065657163756 + 20065657163757.

It is an arithmetic number, because the mean of its divisors is an integer number (20065657163757).

Almost surely, 240131314327513 is an apocalyptic number.

It is an amenable number.

40131314327513 is a deficient number, since it is larger than the sum of its proper divisors (1).

40131314327513 is an equidigital number, since it uses as much as digits as its factorization.

40131314327513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90720, while the sum is 38.

The spelling of 40131314327513 in words is "forty trillion, one hundred thirty-one billion, three hundred fourteen million, three hundred twenty-seven thousand, five hundred thirteen".